QUOTE(rani aapi @ Mar 28 2008, 05:36 PM)

Let us suppose
a=b=1
so v can write
a^2=ab (as a^2 and ab is equal to 1)
Now subtract b^2 on both sides
So the equation will be
a^2-b^2=ab-b^2
As v all know a^2-b^2=(a+b )(a-b)
So using this formula ,we get
(a+b) (a-b)=ab-b^2
=> (a+b)(a-b)=b(a-b)
Now (a-b) is cancelled from both sides or v can say divide(a-b) on both sides
The equation will be as follows
=> (a+b)=b
as a=1 , b=1
So
1+1=1
2=1
Add 63 on both sides
63+2=63+1
=> 65= 64
Hence proved
waisey tu ba-zahir yeah calculation bilkul theek hey,,, lakin B.Sc main jab yeah pahli dafa daikha tu,,, tu ham ne apney maths ke teacher se discuss kya tha,,,, aur uss ne darmian se kissi point ke barey main kaha tha,,, ja aap ne kuch suppose kya hota hey,,, tu aap yeah step nahin ker saktey,,,, exactly yaad nahin,,,,,,,, 12-13 saal purani baat hey